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(1) 230VAC
230VAC we know is root mean square value of sine wave voltage
(2) Circuit
Make a circuit as following

Diode will cut-off half of power source. Resistor voltage will be half of power source, so:

(3) Resistor calculation
Assume that, current need to flow through LED is 20mA
     (a) Value of Resistor
     (b) Power of Resistor:

One solution to choose Resistor with 5.6KOhm 2W
It is maybe make the Resistor hot and burn soon

So, we can divide into 2 Resistors with 2.7KOhm 2W
-> Those 2 resistors can load upto 4W

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